# A Collection of Bit Programming Interview Questions solved by Dr Antonio Gulli PDF By Dr Antonio Gulli

ISBN-10: 1495330729

ISBN-13: 9781495330728

Bits is the second one of a sequence of 25 Chapters dedicated to algorithms, challenge fixing, and C++ programming. This publication is set low point bit programming

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The former one is the highest power of 2 not greater than x (say and it is represented by encoding the number with gamma encoding. The latter one is the remaining binary digit representing . Code void deltaEncoding(unsigned int x) { int len = 0, lengthOfLen = 0, i; for (int i = x; i > 0; i >>= 1) // 1+floor(log2(num)) len++; for (int i = len; i > 1; i >>= 1) // floor(log2(len)) lengthOfLen++; for (int i = lengthOfLen; i > 0; --i) std::cout << 0; for (int i = lengthOfLen; i >= 0; --i) std::cout << ((len >> i) & 1); for (int i = len - 2; i >= 0; i--) std::cout << ((x >> i) & 1); } 28.

In C and C++ this causes an array index out of bounds with unpredictable results. In other languages this situation will throw and exception. The solution is to compute: It is quite amazing to think that it took more than 60 years to detect a bug in a piece of code so commonly used in the industry and studied by generations of students and academics!! ABOUT THE AUTHOR An experienced data mining engineer, passionate about technology and innovation in consumers’ space. Interested in search and machine learning on massive dataset with a particular focus on query analysis, suggestions, entities, personalization, freshness and universal ranking.

Count the number of bits set in an unsigned number Solution We can simply loop and count the bits with complexity, where is the number of bits in the unsigned. Code unsigned int countBits(unsigned int n) { unsigned int count = 0; while (n) { count += n & 1; n >>= 1; } return count; } Solution for sparse bitmaps This solution works better for sparse unsigned s because it runs in a time proportional to the number of bits set to 1. The line n &= (n – 1) sets the rightmost 1 in the bitmap to 0. Code unsigned int countBitsSparse(unsigned int n) { unsigned int count = 0; while (n) { count++; n &= (n - 1); } return count; } Solution for dense bitmaps This solution works better for dense bitmaps because it runs in a time proportional to the number of bits set to 0.